document.write( "Question 337824: Susan paid for her library fine with 12 coins consisting of nickels and dimes. If the fine was $0.95, how many coins were nickels? \n" ); document.write( "
Algebra.Com's Answer #242196 by Alan3354(69443)\"\" \"About 
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Susan paid for her library fine with 12 coins consisting of nickels and dimes. If the fine was $0.95, how many coins were nickels?
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\n" ); document.write( "The hard way:
\n" ); document.write( "n = nickels, d = dimes
\n" ); document.write( "n + d = 12
\n" ); document.write( "5n + 10d = 95 --> n + 2d = 19
\n" ); document.write( "n + 2d = 19
\n" ); document.write( "n + d = 12
\n" ); document.write( "------------ Subtract
\n" ); document.write( "d = 7
\n" ); document.write( "n = 5
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\n" ); document.write( "The easy way:
\n" ); document.write( "12 nickels = 60 cents
\n" ); document.write( "Each nickel replaced by a dime adds 5 cents
\n" ); document.write( "95-60 = 35
\n" ); document.write( "35/5 = 7
\n" ); document.write( "--> 7 dimes, 5 nickels
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