document.write( "Question 337535: A new movies theater after several months of incrementing finds that for every 20 c increase in ticket price the number of tickets for each showing decrease by 10. Similarly for every 20 c decrease in price showings increase by 10. On average the theater sells 500 tickets at $ 8 each. \r
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document.write( "how much should they charge for a ticket to maximize the revenue.?
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document.write( "Also explain how ticket price is related to total revenue?\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #242111 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Revenue = f ( Ticket Price, Tickets Sold ) = Price*Sold \r \n" ); document.write( "\n" ); document.write( "Tickets Sold = f ( Price ) = m*Price + b \n" ); document.write( "Sold = -10/(0.2)*(Price) +b \n" ); document.write( "500 = -10/(0.2)*(8) + b \n" ); document.write( "900 = b \n" ); document.write( "Ticket Sold = -10/(0.2)*Price + 900 \n" ); document.write( "Tickets Sold = -50*Price + 900\r \n" ); document.write( "\n" ); document.write( "Revenue = Price * Sold = Price * (-50*Price + 900) \n" ); document.write( "Revenue = -50*Price^2 + 900*Price\r \n" ); document.write( "\n" ); document.write( "Take the derivative and set to 0: \n" ); document.write( "dRev = -100*Price + 900 \n" ); document.write( "0 = -100*Price+900 \n" ); document.write( "Price = 9.00\r \n" ); document.write( "\n" ); document.write( "This is a maximum because the second derivative is negative: \n" ); document.write( "d^2Rev = -100 \n" ); document.write( " \n" ); document.write( " |