document.write( "Question 38057: DRAW THE GRAPH OF A DIRECT VARIATION THAT INCLUDES THE GIVEN POINT.
\n" ); document.write( "A. (-2,5)
\n" ); document.write( "B. (3,2) \n" ); document.write( "
Algebra.Com's Answer #24210 by Nate(3500)\"\" \"About 
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(-2,5),(3,2)
\n" ); document.write( "slope = (5-2)/(-2-3) = 3/(-5)
\n" ); document.write( "Use point-slope form:
\n" ); document.write( "y-5=(-3/5)(x+2)
\n" ); document.write( "y=(-3/5)x-(6/5)+5
\n" ); document.write( "y=(-3/5)x+(19/5)
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"0.6+x+%2B+1+y+=+3.8\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-0.6%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3.8/0.6 = 6.33333333333333.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3.8/1 = 3.8.
  • Slope is -0.6/1 = -0.6.
  • Equation in slope-intercept form: y=-0.6*x+3.8.
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