document.write( "Question 38654: ellipse problem #11 find vertices, foci
\n" ); document.write( "2x^2+y^2=3\r
\n" ); document.write( "\n" ); document.write( "I can't figure out how to put in (x^2/a^2)+(y^2/b^2)=1 form. How do I get rid of the 2 from 2x? and make 3 into 1?
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Algebra.Com's Answer #24205 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
\"2%28x%5E2%29+%2B+%28y%5E2%29+=+3\"
\n" ); document.write( "\"%282%28x%5E2%29%29%2F3+%2B+%28y%5E2%29%2F3+=+3%2F3\"
\n" ); document.write( "\"%28x%5E2%29%2F%283%2F2%29+%2B+%28y%5E2%29%2F3+=+1\"
\n" ); document.write( "Center is (0,0)
\n" ); document.write( "The major axis is vertical
\n" ); document.write( "\"a+=+sqrt%283%29\"
\n" ); document.write( "\"b+=+sqrt%281.5%29\"
\n" ); document.write( "\"c%5E2+=+a%5E2+-+b%5E2\"
\n" ); document.write( "\"c%5E2+=+%28sqrt%283%29%29%5E2+-+%28sqrt%281.5%29%29%5E2\"
\n" ); document.write( "\"c%5E2+=+%283%29+-+%281.5%29\"
\n" ); document.write( "\"c+=+sqrt%281.5%29\"
\n" ); document.write( "Vertices: (0,3),(0,-3),(1.5,0),(-1.5,0)
\n" ); document.write( "Foci: (0,1.5),(0,-1.5)
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