document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=337395>Question 337395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The current I is an electrical conductor varies inversely as the resistance R of the conductor. The current is 1/7 ampere when the resistance is 21609 ohms. What is the current when the resistance is 3969 Ohms?\r<BR>\n" );
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document.write( "K=1/7*21609=3087<BR>\n" );
document.write( "I=3087/R= \r<BR>\n" );
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document.write( "How do I use the equation I=3087/R= to find the current when the resistance is 3969 Ohms? I figured out the equation however, I don’t know what to do next. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242007 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> plug the value of r in the equation<BR>\n" );
document.write( "I= 3087/3969<BR>\n" );
document.write( "I =0.77 amps </SPAN>\n" );
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