document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=337550>Question 337550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary. One angle measures 12 more than the other. Find the measures of the angles.\r<BR>\n" );
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document.write( "Y+X=90 DEGREES\r<BR>\n" );
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document.write( "(Y+12)=X\r<BR>\n" );
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document.write( "Y +(Y+12) =90\r<BR>\n" );
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document.write( "2Y+12=90\r<BR>\n" );
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document.write( "2Y =90-12\r<BR>\n" );
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document.write( "Y= 72/2\r<BR>\n" );
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document.write( "Y = 36 THEN PLUG IN EQUATION ABOVE 36+X=90 THEN X=90-36 <BR>\n" );
document.write( "THEN X = 54\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241957 by </B><A HREF=/tutors/aboutme.mpl?userid=chiexpert><B>chiexpert(48)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiexpert><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y+X=90 DEGREES\r<BR>\n" );
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document.write( "(Y+12)=X\r<BR>\n" );
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document.write( "Y +(Y+12) =90\r<BR>\n" );
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document.write( "2Y+12=90\r<BR>\n" );
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document.write( "2Y =90-12\r<BR>\n" );
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document.write( "Y= 72/2\r<BR>\n" );
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document.write( "Y = 36 THEN PLUG IN EQUATION ABOVE 36+X=90 THEN X=90-36 <BR>\n" );
document.write( "THEN X = 54\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );