document.write( "Question 337498: rays PQ and QR are perpendicular. Point s lies in the interior of pqr. if pqs =4+7a and sqr = 9+4a, find pqs and sqr \n" ); document.write( "

Algebra.Com's Answer #241919 by Fombitz(32388) $\"\"$ $\"About$

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$\"PQS%2BSQR=90\"$
\n" ); document.write( " $\"4%2B7a%2B9%2B4a=90\"$
\n" ); document.write( " $\"11a%2B13=90\"$
\n" ); document.write( " $\"11a=77\"$
\n" ); document.write( " $\"a=7\"$
\n" ); document.write( ".
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\n" ); document.write( " $\"PQS=4%2B7a=4%2B49=53\"$ degrees
\n" ); document.write( " $\"SQR=9%2B4a=9%2B28=37\"$ degrees \n" ); document.write( "

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