document.write( "Question 337477: How do I solve the equation, \"2%2F%28x%2B4%29+%2B1\" = \"12%2F%28x%5E2%2B9x%2B20%29\" ?\r
\n" ); document.write( "\n" ); document.write( "2/(X+4) + 1 = 12/(X^2+9X+20)\r
\n" ); document.write( "\n" ); document.write( "1={12/{(X+5)(X+4)} *(X+4)/2]\r
\n" ); document.write( "\n" ); document.write( "1=[{12 (X+4) }/{2(X+4)(X+5)}] … \r
\n" ); document.write( "\n" ); document.write( "(X+4) IS CANCEL AND 12/2 IS 6\r
\n" ); document.write( "\n" ); document.write( "1*(X+5)=[6(1/(X+5)) *(X+5)] MULTIPLY THE INVERSE\r
\n" ); document.write( "\n" ); document.write( "1*(X+5) = 6 SUBTRACT BOTH SIDES WITH 5\r
\n" ); document.write( "\n" ); document.write( "X+5-5 = 6-5\r
\n" ); document.write( "\n" ); document.write( "X=1
\n" ); document.write( "

Algebra.Com's Answer #241879 by chiexpert(48)\"\" \"About 
You can put this solution on YOUR website!
2/(X+4) + 1 = 12/(X^2+9X+20)\r
\n" ); document.write( "\n" ); document.write( "1={12/{(X+5)(X+4)} *(X+4)/2]\r
\n" ); document.write( "\n" ); document.write( "1=[{12 (X+4) }/{2(X+4)(X+5)}] … \r
\n" ); document.write( "\n" ); document.write( "(X+4) IS CANCEL AND 12/2 IS 6\r
\n" ); document.write( "\n" ); document.write( "1*(X+5)=[6(1/(X+5)) *(X+5)] MULTIPLY THE INVERSE\r
\n" ); document.write( "\n" ); document.write( "1*(X+5) = 6 SUBTRACT BOTH SIDES WITH 5\r
\n" ); document.write( "\n" ); document.write( "X+5-5 = 6-5\r
\n" ); document.write( "\n" ); document.write( "X=1
\n" ); document.write( "
\n" );