document.write( "Question 337281: A Carpenter is building a rectangular room with a fixed perimeter of 192ft. What dimensions would yield the maximum area? What is the maximum area?\r
\n" ); document.write( "\n" ); document.write( "the length that would yield the maximum area is ________ ft.
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Algebra.Com's Answer #241790 by stanbon(75887)\"\" \"About 
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A Carpenter is building a rectangular room with a fixed perimeter of 192ft.
\n" ); document.write( "Perimeter = 2(L + W)
\n" ); document.write( "192 = 2(L+W)
\n" ); document.write( "L + W = 96
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\n" ); document.write( "What dimensions would yield the maximum area? What is the maximum area?
\n" ); document.write( "the length that would yield the maximum area is ________ ft.
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\n" ); document.write( "Area = LW
\n" ); document.write( "A = L(96-L)
\n" ); document.write( "A = -L^2+96L
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\n" ); document.write( "Quadratic with a = -1 and b = 96
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\n" ); document.write( "Maximum Area occurs when L = -b/(2a) = -96/(2*-1) = 48
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\n" ); document.write( "If L = 48 ft. and L+W = 96, W = 48 ft.
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\n" ); document.write( "Maximum Area = 48*48 = 2304 sq. ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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