document.write( "Question 337071: British sterling silver is a copper-silver alloy that is 7.5% copper by weight. How many grams of pure copper and how many grams of British sterling silver should be used to prepare 200 grams of a copper-silver alloy that is 10% copper by weight? \n" ); document.write( "
Algebra.Com's Answer #241767 by ankor@dixie-net.com(22740)\"\" \"About 
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British sterling silver is a copper-silver alloy that is 7.5% copper by weight.
\n" ); document.write( " How many grams of pure copper and how many grams of British sterling silver
\n" ); document.write( " should be used to prepare 200 grams of a copper-silver alloy that is 10% copper by weight?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of pure copper required
\n" ); document.write( "then
\n" ); document.write( "(200-x) = amt of 7.5% copper alloy required
\n" ); document.write( ":
\n" ); document.write( "Write a percent copper equation in decimal form
\n" ); document.write( "x + .075(200-x) = .10(200)
\n" ); document.write( "x + 15 - .075x = 20
\n" ); document.write( "x - .075x = 20 - 15
\n" ); document.write( ".925x = 5
\n" ); document.write( "x = \"5%2F.925\"
\n" ); document.write( "x = 5.4 grams of pure copper required
\n" ); document.write( "then
\n" ); document.write( "200 - 5.4 = 194.6 grams of 7.5% alloy required
\n" ); document.write( ":
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\n" ); document.write( "Check solution
\n" ); document.write( "5.4 + .075(194.6) = .10(200)
\n" ); document.write( "5.4 + 14.595 = 20
\n" ); document.write( "19.995 ~ 20 \n" ); document.write( "
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