document.write( "Question 337211: multiply 3xyz2 over 6y4 by 2y over xz4\r
\n" ); document.write( "\n" ); document.write( "My assumption of the equation is written as (for it can be written in other ways also depends on the intent of the writer):\r
\n" ); document.write( "\n" ); document.write( "multiply 3xyz2 over 6y4 by 2y over xz4\r
\n" ); document.write( "\n" ); document.write( "{(3xyz)*(2)/6y4} x {(2y)/(xz4)}\r
\n" ); document.write( "\n" ); document.write( "Or\r
\n" ); document.write( "\n" ); document.write( "{(3xyz^2)/6y^4} x {(2y)/(xz^4)}\r
\n" ); document.write( "\n" ); document.write( "I take it is the later or here it is:
\n" ); document.write( "multiply 3xyz2 over 6y4 by 2y over xz4\r
\n" ); document.write( "\n" ); document.write( "{(3xyz^2)/6y^4} * {(2y)/(xz^4)}=\r
\n" ); document.write( "\n" ); document.write( "[{((3/6) * xyz^2)/y^4} * {((2/1) *y)/xz^4)}]= \r
\n" ); document.write( "\n" ); document.write( "Multiply numerator with numerator and denominator with denominator. consolidate numbers separate from letters. Simplify all numbers to lowest simple numbers. 2 is same as 2 over 1 or 2/1 and 3/6 is same as ½ divisable by 3.\r
\n" ); document.write( "\n" ); document.write( "[{(3/6) *(2/1)} * {(xyz^2*y)/(y^4*xz^4)}]=
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\n" ); document.write( "(1/2)(2/1) * (xy^2z^2) / (xy^4z^4) =number divisible itself is one\r
\n" ); document.write( "\n" ); document.write( "2/2 * x/x*y^2/y^4*z^2/z^4 =\r
\n" ); document.write( "\n" ); document.write( "1*1*(1/y^2)*(1/z^2)=\r
\n" ); document.write( "\n" ); document.write( "1/(y^2*z^2) \r
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Algebra.Com's Answer #241740 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!

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