document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38630>Question 38630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the equation. Round your answers to the nearest hundredth.\r<BR>\n" );
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document.write( "9+1.95^x=40\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24171 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an exponential equation, so you will have to take the log or ln of each side of the equation to convert it from an exponential equation to an ordinary linear equation.  First subtract 9 from each side:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.95%5Ex+=+31 ALIGN=MIDDLE  ALT=\"1.95%5Ex+=+31\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, take the ln of each side.  By the way, taking the log of each side works equally well and gives exactly the same answer!<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+ln+1.95%5Ex+=+ln+31 ALIGN=MIDDLE  ALT=\"+ln+1.95%5Ex+=+ln+31\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "By the third law of logarithms <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln+M%5Ex+=+x+%2A+ln+M ALIGN=MIDDLE  ALT=\"ln+M%5Ex+=+x+%2A+ln+M\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2Aln+1.95+=+ln+31 ALIGN=MIDDLE  ALT=\"x+%2Aln+1.95+=+ln+31\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide each side by ln 1.95:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2Aln+1.95%29%2F%28ln+1.95%29+=+%28ln+31%29%2F%28ln+1.95%29+ ALIGN=MIDDLE  ALT=\"%28x%2Aln+1.95%29%2F%28ln+1.95%29+=+%28ln+31%29%2F%28ln+1.95%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28ln+31%29%2F%28ln+1.95%29+ ALIGN=MIDDLE  ALT=\"x+=+%28ln+31%29%2F%28ln+1.95%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 5.142 approximately.\r<BR>\n" );
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document.write( "Final answer rounded to nearest tenth = 5.1\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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