document.write( "Question 38619: A ship using sound-sensing devices above and below water recorded a surface explosion 39 seconds sooner on its underwater device than on its above-water device. If sound travels in air at about 1100 feet per second and in water at about 5000 feet per second, how far away was the explosion? \n" ); document.write( "
Algebra.Com's Answer #24170 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Letting t be the time: \n" ); document.write( "Equation: \n" ); document.write( "1100t=5000(t-39) \n" ); document.write( "-3900t=-195000 \n" ); document.write( "t=50 \n" ); document.write( "Hence, the explosion is 50ft far away. \n" ); document.write( "Paul. \n" ); document.write( " |