document.write( "Question 337182: I am supposed to find the maximum value of this equation and am not having any
\n" ); document.write( "luck f(x)= -10/3(x+5)^2 - 5 This is what I have y= -10(x+5)^2/3 - 5*3/3, y=
\n" ); document.write( "(-10(x+5)^2)/3 - 15/3, -10x^2-100x-265/3, factor out -5, y= (-5(2x^2 +
\n" ); document.write( "20x+53)/3, this is where I end. Please help me understand Thank-you.
\n" ); document.write( "I think the answer is -5 as the constant - 5 = k in the equation f(x)=a(x-h)^2+k
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Algebra.Com's Answer #241694 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
No, the function is already in vertex form.
\n" ); document.write( "\"a=-10%2F3\"
\n" ); document.write( "\"h=-5\"
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\n" ); document.write( "The min or max value occurs at the vertex.
\n" ); document.write( "Since the coefficient of the \"x%5E2\" term is negative, the parabola opens downwards and the max value is
\n" ); document.write( "\"ymax=k=-5\"
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