document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38602>Question 38602</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Two similar triangles have sides in the ratio of 4:5. What is the ratio of their perimeters?\r<BR>\n" );
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document.write( "A regular square pyramid has a base with edges 16 and height 15. What is the volume and surface area of the pyramid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24165 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two similar triangles have sides in the ratio of 4:5. What is the ratio of their perimeters?<BR>\n" );
document.write( "LET THE SIDES BE 4X,4Y,4Z AND 5X,5Y,5Z<BR>\n" );
document.write( "PERIMETER RATIO=4(X+Y+Z)/5(X+Y+Z)=4/5<BR>\n" );
document.write( "A regular square pyramid has a base with edges 16 and height 15. What is the volume and surface area of the pyramid?<BR>\n" );
document.write( "VOLUME =BASE AREA*HEIGHT/3=16*16*15/3=1280 <BR>\n" );
document.write( "LET ABCD BE THE SQUARE BASE AND T BE THE VERTEX.THE ALTITUDE TS FROM TOP TO BASE WILL MEET THE BASE AT S THE POINT OF INTERSECTION OF DIAGONALS AC AND BD.<BR>\n" );
document.write( "LET MIDPOINT OF AB BE P.THEN PT IS THE SLANT HEIGHT<BR>\n" );
document.write( "IN RIGHT TRIANGLE PST,WE HAVE<BR>\n" );
document.write( "PT^2=PS^2+ST^2=8^2+15^2=64+225=289<BR>\n" );
document.write( "PT=17<BR>\n" );
document.write( "HENCE AREA OF ONE SLANT SURFACE ABT=0.5*16*17=136<BR>\n" );
document.write( "TOTAL SLANT AREA=4*136=544 </SPAN>\n" );
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