document.write( "Question 337102: A 95% confidence interval estimate for a population mean was computed to be (36.5 to 56.0). Determine the mean of the sample, which was used to determine the interval estimate (show all work).
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Algebra.Com's Answer #241637 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The formula for a 95% confidence interval is\r\n" );
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document.write( "(xbar-1.96*\"sigma%2Fsqrt%28n%29\", xbar+1.96*\"sigma%2Fsqrt%28n%29\") \r\n" );
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document.write( "So if you add the two endpoints of a confidence interval\r\n" );
document.write( "you will get 2xbar because the 1.96*\"sigma%2Fsqrt%28n%29\" and the\r\n" );
document.write( "-1.96*\"sigma%2Fsqrt%28n%29\" will cancel. So you just divide the \r\n" );
document.write( "sum of the endpoints of the confidence interval by 2 and that \r\n" );
document.write( "will give you the sample mean xbar.\r\n" );
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document.write( "IOW the midpoint of the confidence interval is the sample mean,\r\n" );
document.write( "so you just average the endpoints of the confidence interval,\r\n" );
document.write( "and that will give the sample mean.\r\n" );
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document.write( "Sample mean = xbar =\"%2836.5%2B56.0%29%2F2+=+46.25\"\r\n" );
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document.write( "Edwin
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