document.write( "Question 336969: If my car always goes 94 kilometers per hour and I stop at a rest stop for 21 minutes, and I only average 84.9 kilometers per hour on my trip; how many total kilometers did I go and how many hours did it take? \n" ); document.write( "
Algebra.Com's Answer #241618 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
\n" ); document.write( "\"R%2At=D\"
\n" ); document.write( "t1 is the time while the car moves at 94 kph.
\n" ); document.write( "\"94%2At1=D\"
\n" ); document.write( "\"t1=D%2F94\"
\n" ); document.write( "The units are in hours, let's convert to minutes.
\n" ); document.write( "\"t1=%2860%2F94%29D=%2830%2F47%29D\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "t2 is the time at rest.
\n" ); document.write( "\"t2=21\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Average speed is total distance divided by total time.
\n" ); document.write( "\"D%2F%28t1%2Bt2%29=84.9%2F60=849%2F600=283%2F200\"
\n" ); document.write( "\"D%2F%28%2830%2F47%29D%2B21%29=283%2F200\"
\n" ); document.write( "\"200D=283%28%2830%2F47%29D%2B21%29\"
\n" ); document.write( "Multiply both side by \"47\"
\n" ); document.write( "\"47%28200D%29=283%2830D%2B47%2A21%29\"
\n" ); document.write( "\"9400D=8490D%2B279321\"
\n" ); document.write( "\"9210D=279321\"
\n" ); document.write( "\"D=306.95\"km
\n" ); document.write( "Then from above,
\n" ); document.write( "\"t1=%2830%2F47%29%28306.95%29=195.9\" minutes
\n" ); document.write( "\"t=t1%2Bt2=195.9%2B21=216.9\" minutes
\n" ); document.write( "\"t=3.61\" hrs
\n" ); document.write( "\"t\"=\"3\" hrs \"37\" minutes.
\n" ); document.write( "
\n" ); document.write( "
\n" );