document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=337085>Question 337085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A marketing company uses to photocopiers to make 30,000 copies for advertising. One copier can produce 3000 copies per hour. What is the hourly rate of the second copier if together they take 4 hours to produce the advertising? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241596 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A marketing company uses to photocopiers to make 30,000 copies for advertising. One copier can produce 3000 copies per hour. What is the hourly rate of the second copier if together they take 4 hours to produce the advertising?<BR>\n" );
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document.write( "Fact: rate *time = # produced<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3000*4 + r*4 = 30,000<BR>\n" );
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document.write( "4r = 30,000-12000<BR>\n" );
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document.write( "4r = 18,000<BR>\n" );
document.write( "r = 4500 per hour (rate of the 2nd copier)<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );