document.write( "Question 337047: can anyone help me to find this answer?? \r
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document.write( "a production editor at a textbook publishing house decided that the pages of abook should have 1-inch margins at the top and bottom and 0.5-inch margins on the side. she further stipulated that the length of a page should be 1.5 times its width and have a printed area of exactly 51 square inches.find the dimensions of a page of the book\r
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document.write( "thank you... \n" );
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Algebra.Com's Answer #241574 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the width be x \n" ); document.write( "the length will be 1.5x \n" ); document.write( ".. \n" ); document.write( "Side Margin = 0.5 inch. 1 \" total \n" ); document.write( "Top margin 1 \" bottom 1\" = 2 inches. \n" ); document.write( "Printing area = (x-1)(1.5x-2)=51 \n" ); document.write( "1.5x^2-2x-1.5x+2=51 \n" ); document.write( "1.5x^2-3.5x+2=51 \n" ); document.write( "multiply by 2\r \n" ); document.write( "\n" ); document.write( "3x^2-7x+4=102 \n" ); document.write( "3x^2-7x-98=0 \n" ); document.write( "3x^2-21+14x-98=0 \n" ); document.write( "3x(x-7)+14(x-7)=0 \n" ); document.write( "(x-7)(3x+14) \n" ); document.write( "x= 7 ignore -14/3 \n" ); document.write( "printing dimensions = 7\" & 10.5 \" \n" ); document.write( " |