document.write( "Question 337054: How much 20% antifreeze solution must be added to 20 liters of 50% antifreeze solution to reduce it to 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #241569 by mananth(16946)\"\" \"About 
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20% antifreeze solution x liters
\n" ); document.write( "20 liters of 50% antifreeze solution
\n" ); document.write( "40% antifreeze 20 + x liters
\n" ); document.write( "..
\n" ); document.write( "0.2x+0.5*20=0.4(20+x)
\n" ); document.write( "0.2x+10=8 +0.4x
\n" ); document.write( "add -0.2x
\n" ); document.write( "0.2x-0.2x+10=0.4x-0.2x+8
\n" ); document.write( "10=0.2x+8
\n" ); document.write( "add -8
\n" ); document.write( "10-8 = 0.2x +8-8
\n" ); document.write( "2=0.2x
\n" ); document.write( "divide by 0.2
\n" ); document.write( "10=x
\n" ); document.write( "10 liters\r
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