document.write( "Question 337054: How much 20% antifreeze solution must be added to 20 liters of 50% antifreeze solution to reduce it to 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #241569 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 20% antifreeze solution x liters \n" ); document.write( "20 liters of 50% antifreeze solution \n" ); document.write( "40% antifreeze 20 + x liters \n" ); document.write( ".. \n" ); document.write( "0.2x+0.5*20=0.4(20+x) \n" ); document.write( "0.2x+10=8 +0.4x \n" ); document.write( "add -0.2x \n" ); document.write( "0.2x-0.2x+10=0.4x-0.2x+8 \n" ); document.write( "10=0.2x+8 \n" ); document.write( "add -8 \n" ); document.write( "10-8 = 0.2x +8-8 \n" ); document.write( "2=0.2x \n" ); document.write( "divide by 0.2 \n" ); document.write( "10=x \n" ); document.write( "10 liters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |