document.write( "Question 337057: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and B is traveling at 70 miles per hour. Train A passes the station at 3:15pm. If Train B passes the station at 3:27, what time will Train B catch up to Train A? \n" ); document.write( "
Algebra.Com's Answer #241567 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let train B meet train A at x miles distance \n" ); document.write( "during that time train A travels x-12 miles \n" ); document.write( "because it was 12 minutes early at the station. \n" ); document.write( "In12 minutes it travels 12 miles. ( 60 mph)\r \n" ); document.write( "\n" ); document.write( "x/70 = x-12/60 \n" ); document.write( "60x= 70(x-12) \n" ); document.write( "60x= 70x-840 \n" ); document.write( "add 840 to both sides \n" ); document.write( "60x+840=70x+840-840 \n" ); document.write( "60x+840 =70x \n" ); document.write( "add -60x \n" ); document.write( "60x-60x+840 = 70x -60x \n" ); document.write( "10x =840 \n" ); document.write( "divide by 10 \n" ); document.write( "x= 84 \n" ); document.write( ".. \n" ); document.write( "train B speed = 70 mph \n" ); document.write( "distance = 84 miles \n" ); document.write( "time taken = 84/70 =1.2 hours 1 hour 12 minutes \n" ); document.write( "train B will catch up with train A at 4:39 pm \n" ); document.write( " |