document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37893>Question 37893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has an inscribed right triangle having an altitude of 4 and an area of 28. What are the circumference and area of circle? (Inscribes means inside with vertex's touching the edsge of the circle) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24156 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a right triangle is inscribed in a circle, then the legs of that right triangle will be the base and altitude of the triangle, and the hypotenuse of the right triangle will be the diameter of the circle.  To find the area and circumference of the circle, you need to find the diameter (and radius!) of the circle.\r<BR>\n" );
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document.write( "If altitude = 4 and area = 28, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=+%281%2F2%29%2Ab%2Ah ALIGN=MIDDLE  ALT=\"A=+%281%2F2%29%2Ab%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28+=+%281%2F2%29%2A+4%2Ah ALIGN=MIDDLE  ALT=\"28+=+%281%2F2%29%2A+4%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28=2h ALIGN=MIDDLE  ALT=\"28=2h\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=+14 ALIGN=MIDDLE  ALT=\"h=+14\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Next, Let d= diameter of the circle, which is also the hypotenuse of the right triangle.  According to the Theorem of Pythagoras:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+%2B+b%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2+%2B+b%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%5E2+%2B+14%5E2+=+d%5E2 ALIGN=MIDDLE  ALT=\"4%5E2+%2B+14%5E2+=+d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16+%2B+196+=+d%5E2 ALIGN=MIDDLE  ALT=\"16+%2B+196+=+d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=212+=+d%5E2 ALIGN=MIDDLE  ALT=\"212+=+d%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d+=+sqrt%28212%29+=+2%2Asqrt%2853%29+ ALIGN=MIDDLE  ALT=\"d+=+sqrt%28212%29+=+2%2Asqrt%2853%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Remember that the radius is HALF of the diameter, so if r= the radius, then <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=+sqrt%2853%29+ ALIGN=MIDDLE  ALT=\"r=+sqrt%2853%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+53 ALIGN=MIDDLE  ALT=\"r%5E2+=+53\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=+pi%2Ar%5E2=++pi%2A53+=+53%2Api ALIGN=MIDDLE  ALT=\"A=+pi%2Ar%5E2=++pi%2A53+=+53%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > square units.\r<BR>\n" );
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document.write( "Circumference = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+pi%2Ad=+pi%2A+2%2Asqrt%2853%29+=2%2Api%2Asqrt%2853%29+ ALIGN=MIDDLE  ALT=\"C+=+pi%2Ad=+pi%2A+2%2Asqrt%2853%29+=2%2Api%2Asqrt%2853%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > units.  \r<BR>\n" );
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document.write( "R^2 at SCC\r<BR>\n" );
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document.write( " </SPAN>\n" );
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