document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=337035>Question 337035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars traveling in the same direction leave the same point at the same time. Car 1 is going 65 km/h and Car 2 is going 55 km/h. How far must Car 1 travel before it has a 15 min. lead on Car 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241557 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since the cars are travelling in same direction Car 1 gains 10 km every hour.<BR>\n" );
document.write( "in 1/4 hour it will gain 10/(1/4)= 2.5 km.<BR>\n" );
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document.write( "Let car 1 travel x km at speed of 65 km/h<BR>\n" );
document.write( "car2  will travel x-2.5 km in the same time<BR>\n" );
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document.write( "time = distance /speed<BR>\n" );
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document.write( "x/65 = (x-2.5)/55<BR>\n" );
document.write( "55x=65(x-2.5)<BR>\n" );
document.write( "55x=65x-162.5<BR>\n" );
document.write( "add -65x<BR>\n" );
document.write( "55x-65x=65x-65x-162.5<BR>\n" );
document.write( "-10x=-162.5<BR>\n" );
document.write( "divide by -10<BR>\n" );
document.write( "x= -162.5/-10<BR>\n" );
document.write( "x=16.25 km. the distance car 1 has to travel to be 15 minutes ahead.<BR>\n" );
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