document.write( "Question 336686: A bus traveled at an average rate of 50 mph and then reduced its rate to 40 mph for the rest of thetrip. If the 220-mile trip took 5 hours, determine how long the bus traveled at each rate. \n" ); document.write( "
Algebra.Com's Answer #241539 by ankor@dixie-net.com(22740)\"\" \"About 
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A bus traveled at an average rate of 50 mph and then reduced its rate to 40 mph for the rest of the trip.
\n" ); document.write( " If the 220-mile trip took 5 hours, determine how long the bus traveled at each rate.
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\n" ); document.write( "Let t = time at 50 mph rate
\n" ); document.write( "then
\n" ); document.write( "(5-t) = time at 40 mph rate
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\n" ); document.write( "Write a distance equation: dist = speed * time
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\n" ); document.write( "50 mph dist + 40 mph dist = 220 mi
\n" ); document.write( "50t + 40(5-t) = 220
\n" ); document.write( "50t + 200 - 40t = 220
\n" ); document.write( "50t - 40t = 220 - 200
\n" ); document.write( "10t = 20
\n" ); document.write( "t = 2 hrs at 50 mph
\n" ); document.write( "then
\n" ); document.write( "5 - 2 = 3 hrs at 40 mph
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\n" ); document.write( "Check solution by finding the distances
\n" ); document.write( "50(2) = 100
\n" ); document.write( "40(3) = 120
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\n" ); document.write( "total: 220 \n" ); document.write( "
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