document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=336995>Question 336995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem. The volume V of a gas varies inversely as the pressure P on it. The volume of a gas is 240 cm3 under a pressure of 23 kg/cm2  What will be its volume under a pressure of 30 kg/cm2?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241533 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume V of a gas varies inversely as the pressure P on it. The volume of a gas is 240 cm3 under a pressure of 23 kg/cm2 What will be its volume under a pressure of 30 kg/cm2? <BR>\n" );
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document.write( "V = k/P<BR>\n" );
document.write( "240 = k/23<BR>\n" );
document.write( "k = 5520<BR>\n" );
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document.write( "At P = 30:<BR>\n" );
document.write( "V = 5520/30<BR>\n" );
document.write( "V = 184 cc<BR>\n" );
document.write( " </SPAN>\n" );
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