document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=336763>Question 336763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Each of the two congruent sides of an isosceles triangle is 7cm. longer then half the base. If the perimeter of the triangle is 50cm. Find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241472 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(B+7)/2+B=50<BR>\n" );
document.write( "B+7+B=50<BR>\n" );
document.write( "2B=50-7<BR>\n" );
document.write( "2B=43<BR>\n" );
document.write( "B=43/2<BR>\n" );
document.write( "B=21.5 ANS. FOR THE BASE.<BR>\n" );
document.write( "(21.5+7)/2=28.5/2=14.25 ANS. FOR THE 2 SIDES.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2(21.5+7)/2+21.5=50<BR>\n" );
document.write( "2(28.5)/2+21.5=50<BR>\n" );
document.write( "28.5+21.5=50<BR>\n" );
document.write( "50=50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );