document.write( "Question 336769: How many hours will a car traveling at 45 miles per hour take to catch up with a car travelling at 30 miles per hour if the slower car starts one hour before the faster car? \n" ); document.write( "
Algebra.Com's Answer #241463 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=45T \n" ); document.write( "D=30(T+1) \n" ); document.write( "45T=30(T+1) \n" ); document.write( "45T=30T+30 \n" ); document.write( "45T-30T=30 \n" ); document.write( "15T=30 \n" ); document.write( "T=30/15 \n" ); document.write( "T=2 HOURS TO CATCH THE SLOWER CAR. \n" ); document.write( "PROOF: \n" ); document.write( "45*2=30(2+1) \n" ); document.write( "90=30*3 \n" ); document.write( "90=90\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |