document.write( "Question 336769: How many hours will a car traveling at 45 miles per hour take to catch up with a car travelling at 30 miles per hour if the slower car starts one hour before the faster car? \n" ); document.write( "
Algebra.Com's Answer #241463 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "D=45T
\n" ); document.write( "D=30(T+1)
\n" ); document.write( "45T=30(T+1)
\n" ); document.write( "45T=30T+30
\n" ); document.write( "45T-30T=30
\n" ); document.write( "15T=30
\n" ); document.write( "T=30/15
\n" ); document.write( "T=2 HOURS TO CATCH THE SLOWER CAR.
\n" ); document.write( "PROOF:
\n" ); document.write( "45*2=30(2+1)
\n" ); document.write( "90=30*3
\n" ); document.write( "90=90\r
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