document.write( "Question 336804: Can you please help me factor this polynomial?\r
\n" ); document.write( "\n" ); document.write( "8x^2 + 16x +12 thank you!
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Algebra.Com's Answer #241412 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"8x%5E2%2B16x%2B12\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"4%282x%5E2%2B4x%2B3%29\" Factor out the GCF \"4\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"2x%5E2%2B4x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"2x%5E2%2B4x%2B3\" we can see that the first term is \"2x%5E2\" and the last term is \"3\" where the coefficients are 2 and 3 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 2 and the last coefficient 3 to get 6. Now what two numbers multiply to 6 and add to the middle coefficient 4? Let's list all of the factors of 6:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 6:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 6\r
\n" ); document.write( "\n" ); document.write( "1*6\r
\n" ); document.write( "\n" ); document.write( "2*3\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-6)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-3)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4\r
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First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5
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\n" ); document.write( "\n" ); document.write( "None of these pairs of factors add to 4. So the expression \"2x%5E2%2B4x%2B3\" cannot be factored\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"8x%5E2%2B16x%2B12\" factors to \"4%282x%5E2%2B4x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my website. \r
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\n" ); document.write( "\n" ); document.write( "Jim
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