document.write( "Question 336726: How can I solve 4x^2 + 48x +104 = 0 by applying the quadratic formula? \n" ); document.write( "
Algebra.Com's Answer #241385 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"4x%5E2+%2B+48x+%2B104+=+0\"\r\n" );
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document.write( "To make things easier, divide every term by 4\r\n" );
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document.write( "\"4x%5E2%2F4%2B48x%2F4%2B104%2F4=0%2F4\"\r\n" );
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document.write( "\"x%5E2%2B12x%2B26=0\"\r\n" );
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document.write( "\"a=1\", \"b=12\", \"c=26\"\r\n" );
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document.write( "\"x+=+%28-12+%2B-+sqrt%28+12%5E2-4%2A1%2A26+%29%29%2F%282%2A1%29+\"\r\n" );
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document.write( "\"x+=+%28-12+%2B-+sqrt%28144-104+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-12+%2B-+sqrt%2840+%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-12+%2B-+sqrt%284%2A10%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-12+%2B-+2sqrt%2810%29%29%2F2+\" \r\n" );
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document.write( "Factor 2 out of the top:\r\n" );
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document.write( "\"x+=+%282%28-6+%2B-+sqrt%2810%29%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28cross%282%29%28-6+%2B-+sqrt%2810%29%29%29%2Fcross%282%29+\"\r\n" );
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document.write( "\"x+=+-6+%2B-+sqrt%2810%29%29+\"\r\n" );
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document.write( "The two solutions are \r\n" );
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document.write( "\"x+=+-6+%2B+sqrt%2810%29%29+\" and \"x+=+-6+-+sqrt%2810%29%29+\"\r\n" );
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document.write( "Edwin

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