document.write( "Question 335951: A farmer has 1000 feet of fence to enclose a rectangular area. What dimensions for the rectangle result in the maximum area enlosed by the fence? \n" ); document.write( "
Algebra.Com's Answer #241356 by Fombitz(32388)\"\" \"About 
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The perimeter of the rectangle is,
\n" ); document.write( "\"P=2L%2B2W=1000\"
\n" ); document.write( "\"L%2BW=500\"
\n" ); document.write( "The area of a rectangle is,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "From the perimeter equation,
\n" ); document.write( "\"L=500-W\"
\n" ); document.write( "\"A=%28500-W%29W=500W-W%5E2\"
\n" ); document.write( "Convert the area function to vertex form (\"y=a%28x-h%29%5E2%2Bk\")to get the maximum value, which occurs at the vertex (\"h\",\"k\").
\n" ); document.write( "\"A%28W%29=500W-W%5E2=-%28W%5E2-500W%29\"
\n" ); document.write( "\"A%28W%29=-%28W%5E2-500W%2B62500%29%2B62500\"
\n" ); document.write( "\"A%28W%29=-%28W-250%29%5E2%2B62500\"
\n" ); document.write( "The maximum area occurs when \"W=250\"ft and is equal to \"A=62500\".
\n" ); document.write( "\"L=500-250\"
\n" ); document.write( "\"L=250\"ft
\n" ); document.write( "The maximum area for a given perimeter is a square.
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