document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=336695>Question 336695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which number cannot be used in place of the variablein each rational express<BR>\n" );
document.write( "2y + 1<BR>\n" );
document.write( "y^2-y-6e </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241345 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) Any irrational value for y will result in an irrational result.<BR>\n" );
document.write( "2) No value fro y will result in a rational number (that I can see). If one could find a value for y that resulted in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2-y+=+6e ALIGN=MIDDLE  ALT=\"y%5E2-y+=+6e\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then that would work. Otherwise, e is irrational, subtracting that from anything that isn't exactly 6e seems to me to end up being irrational<BR>\n" );
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