document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=336536>Question 336536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train travels 295 mi in the same amount of time it takes a freight train to travel 225 mi. The rate of the passenger train is 14 mph greater than the rate of the freigh train. Find the rate of each train.\r<BR>\n" );
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document.write( "           	Distance	Rate	Time<BR>\n" );
document.write( "passenger	295	14+r	        295<BR>\n" );
document.write( "                                        14+r\r<BR>\n" );
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document.write( "freight	295	r	225               225<BR>\n" );
document.write( "                                          r              \r<BR>\n" );
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document.write( "                                                                <BR>\n" );
document.write( "295    +     225  =  ?<BR>\n" );
document.write( "14+r          r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241246 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let f=rate of the freight train, r=rate, d=distance, t=time<BR>\n" );
document.write( "rt=d<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "295/(f+14)=225/f Since the times are equal.<BR>\n" );
document.write( "295f=225(f+14)<BR>\n" );
document.write( "295f=225f+3150<BR>\n" );
document.write( "70f=3150<BR>\n" );
document.write( "f=45 mph<BR>\n" );
document.write( "f+14=59 mph<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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