document.write( "Question 336525: How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #241240 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 80*.8=64 total liters alcohol in 80% soln. \n" ); document.write( "x *.1=.1x total liters alcohol in 10% soln. \n" ); document.write( "(80+x)*.5=40+.5x total liters alcohol in 50% soln. \n" ); document.write( ". \n" ); document.write( "64+.1x=40+.5x \n" ); document.write( "24=.4x \n" ); document.write( "x=60 L of the 10% alcohol must be added. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |