document.write( "Question 336525: How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #241240 by edjones(8007)\"\" \"About 
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80*.8=64 total liters alcohol in 80% soln.
\n" ); document.write( "x *.1=.1x total liters alcohol in 10% soln.
\n" ); document.write( "(80+x)*.5=40+.5x total liters alcohol in 50% soln.
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\n" ); document.write( "64+.1x=40+.5x
\n" ); document.write( "24=.4x
\n" ); document.write( "x=60 L of the 10% alcohol must be added.
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