document.write( "Question 38596: Add:\r
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Algebra.Com's Answer #24124 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
In order to ADD fractions, you must have a common denominator. This means a number that each of the denominators divides evenly into. You need to find a number that 3, 12, and 5 all divide evenly. One way to do this is to take MULTIPLES of the largest number, which is 12, and keep going until you find a number that can be also divided by 3 and 5. This means start with 12, 24, 36, 48, 60, etc. Did you see that 60 can be divided by 3 and 5? \r
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\n" ); document.write( "\n" ); document.write( "Now, you need to change each fraction 1/3, 5/12, and 4/5 into fractions whose denominator is 60. To do this, the denominator 3 must be multiplied by 20, the denominator 12 must be multiplied by 5, and the denominator 5 must be multiplied by 12. It looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F3+%2B+5%2F12+%2B+4%2F5\"
\n" ); document.write( "\"%281%2F3%29%2A%2820%2F20%29+%2B+%285%2F12%29%2A%285%2F5%29+%2B+%284%2F5%29%2A%2812%2F12%29+\"\r
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\n" ); document.write( "\n" ); document.write( "What this means is that you have:
\n" ); document.write( "\"20%2F60+%2B+25%2F60+%2B+48%2F60+\"\r
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\n" ); document.write( "\n" ); document.write( "Now add up all these numerators, and put the answer over the common denominator which is 60:\r
\n" ); document.write( "\n" ); document.write( "\"+%2820%2B25%2B48%29%2F60\"
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\n" ); document.write( "\n" ); document.write( "The fraction reduces since you can divide both 93 and 60 by 3:
\n" ); document.write( "\"31%2F20\" \r
\n" ); document.write( "\n" ); document.write( "This is an improper fraction, which is actually preferred in higher math, but in lower math they might want a mixed fraction. You may want to write this as
\n" ); document.write( "\"1+\" \"11%2F20\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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