document.write( "Question 336523: on a recent trip, Sararh's car traveled 20 mph faster on the first 110 miles than it did on the remaining 80 miles. The total time for the trip was 4 hr. Find the speed of Sarah's car on the first part of the trip. \n" ); document.write( "
Algebra.Com's Answer #241235 by Fombitz(32388)\"\" \"About 
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Rate*Time=Distance
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\n" ); document.write( "\"R1%2AT1=D1\"
\n" ); document.write( "\"R2%2AT2=D2\"
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\n" ); document.write( "\"D1=110%0D%0A%7B%7B%7BD2=80\"
\n" ); document.write( "\"T1%2BT2=4\"
\n" ); document.write( "\"R1=R2%2B20\"
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\n" ); document.write( "Substituting,
\n" ); document.write( "\"%28R2%2B20%29%2AT1=110\"
\n" ); document.write( "\"T1=110%2F%28R2%2B20%29\"
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\n" ); document.write( "\"R2%2AT2=80\"
\n" ); document.write( "\"T2=80%2FR2\"
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\n" ); document.write( "And finally,
\n" ); document.write( "\"T1%2BT2=4\"
\n" ); document.write( "\"110%2F%28R2%2B20%29%2B80%2FR2=4\"
\n" ); document.write( "\"110%2B80%28R2%2B20%29=4%2AR2%2A%28R2%2B20%29\"
\n" ); document.write( "\"110R2%2B80R2%2B1600=4R2%5E2%2B80R2\"
\n" ); document.write( "\"4R%5E2-110R2-1600=0\"
\n" ); document.write( "Use the quadratic formula,
\n" ); document.write( "\"R2+=+%28110+%2B-+sqrt%28+%28110%29%5E2-4%2A4%2A%28-1600%29+%29%29%2F%282%2A4%29+\"
\n" ); document.write( "\"R2+=+%28110+%2B-+sqrt%2812100%2B25600+%29%29%2F%288%29+\"
\n" ); document.write( "\"R2+=+%28110+%2B-+sqrt%2837700%29%29%2F%288%29+\"
\n" ); document.write( "\"R2+=+%28110+%2B-+10sqrt%28377%29%29%2F%288%29+\"
\n" ); document.write( "Only the positive result makes sense for this problem.
\n" ); document.write( "\"R2=%28110%2B10sqrt%28377%29%29%2F8\"
\n" ); document.write( "So then
\n" ); document.write( "\"R1=%28110%2B10sqrt%28377%29%29%2F8%2B20\"
\n" ); document.write( "\"R2=%28270%2B10sqrt%28377%29%29%2F8\" or approximately,
\n" ); document.write( "\"highlight%28R2=58.02%29\"mph
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