document.write( "Question 336559: the length of a rectangular mailing label is 5 cm less than twice the width. The perimeter is 20 cm. find the dimensions of the label \n" ); document.write( "
Algebra.Com's Answer #241211 by Jk22(389)\"\" \"About 
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let l=length, w=width, p=perimeter (in cm)\r
\n" ); document.write( "\n" ); document.write( "data : p=20, l=2w-5\r
\n" ); document.write( "\n" ); document.write( "know : p=2l+2w=2l+l+5=3l+5 (warning : not to read as 21+1=22)\r
\n" ); document.write( "\n" ); document.write( "=> 20=3l+5 => l=5, w=(l+5)/2=5\r
\n" ); document.write( "\n" ); document.write( "hence it were a square of 5cm side.
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