document.write( "Question 336513: A student walks and jogs to college each day. she averages 5km/h walking and 9km/h jogging. the distance from home to college is 8km, and she makes the trip in 1hr. how far does the student jog? \n" ); document.write( "
Algebra.Com's Answer #241208 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let x=fraction of an hour walking. \n" ); document.write( "(5/h * xh)+ (9/h * (1-x)h) = 8 \n" ); document.write( "5x+9-9x=8 \n" ); document.write( "-4x=-1 \n" ); document.write( "x=1/4. \n" ); document.write( "9(1- 1/4)=6.75 km distance the student jogs. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |