document.write( "Question 4603: I can't figure out the . I need help, please!
\n" ); document.write( "It takes Pat 12 hours to complete a task. After he had been working for 3 hours, his brother Mike joined him, and together they finished the job in 5 hours. How long would it take Mike to do the job by himself?
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Algebra.Com's Answer #2412 by Abbey(339)\"\" \"About 
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To find a rate of work, break the problem down into something that can be compared relatively easily. In this case, look at how much work Pat gets done each hour.\r
\n" ); document.write( "\n" ); document.write( "Pat = completes \"1%2F12\" of the work every hour
\n" ); document.write( "Mike's rate of work is not known so we can say
\n" ); document.write( "Mike= completes \"1%2Fx\" of the work every hour.\r
\n" ); document.write( "\n" ); document.write( "Together they work at a rate of 1/5 of the work completed each hour, so:
\n" ); document.write( "\"1%2F12+%2B+1%2Fx+=+1%2F5\"\r
\n" ); document.write( "\n" ); document.write( "Find a common denominator:
\n" ); document.write( "\"5x%2F60x%2B60%2F60x=12x%2F60x\"\r
\n" ); document.write( "\n" ); document.write( "Now we can drop the denominator:
\n" ); document.write( "5x+60=12x
\n" ); document.write( "subtract 5x from both sides:
\n" ); document.write( "60=7x
\n" ); document.write( "divide both sides by 7:
\n" ); document.write( "60/7=x or x=8.57\r
\n" ); document.write( "\n" ); document.write( "so Mike's rate of work is \"1%2F8.57\", so he could finish the job in 8.57 hours by himself.
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