document.write( "Question 336203: On a recent trip, Sarahs car traveled 20 mph faster on the first 200 miles that it did on the remaining 80 miles. The total time for the trip was 4 hours. Find the speed of Sarahs car on the first part of the trip.\r
\n" ); document.write( "\n" ); document.write( "a) 13 mph b) 77 mph c) 68 mph d) 57 mph\r
\n" ); document.write( "\n" ); document.write( "I came up with b) 77 but was not sure if this was correct. Could you please show me the correct way to work this problem out.
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Algebra.Com's Answer #241093 by ankor@dixie-net.com(22740)\"\" \"About 
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On a recent trip, Sarahs car traveled 20 mph faster on the first 200 miles that
\n" ); document.write( " it did on the remaining 80 miles.
\n" ); document.write( " The total time for the trip was 4 hours. Find the speed of Sarahs car on the first part of the trip.
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\n" ); document.write( "Let s = speed on the 1st part of the trip (200 mi)
\n" ); document.write( "then
\n" ); document.write( "(s-20) = speed on the last part (80 mi)
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\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "Fast speed time + slow speed time = 4 hrs
\n" ); document.write( "\"200%2Fs\" + \"80%2F%28%28s-20%29%29\" = 4
\n" ); document.write( "multiply equation by s(s-20),results:
\n" ); document.write( "200(s-20) + 80s = 4s(s-20)
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\n" ); document.write( "200s - 4000 + 80s = 4s^2 - 80s
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\n" ); document.write( "280s - 4000 = 4s^2 - 80s
\n" ); document.write( "A quadratic equation
\n" ); document.write( "0 = 4s^2 - 80s - 280s + 4000
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\n" ); document.write( "4s^2 - 360s + 4000 = 0
\n" ); document.write( "simplify divide by 4
\n" ); document.write( "s^2 - 90s + 1000 = 0
\n" ); document.write( "Solving this with quadratic formula got two solutions: s=13 and s=77
\n" ); document.write( "Obviously s = 77 mph is the one
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\n" ); document.write( "Check it find the time at each speed
\n" ); document.write( "200/77 = 2.6 hr
\n" ); document.write( "80/57 = 1.4 hrs
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\n" ); document.write( "total time 4 hrs
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