document.write( "Question 336180: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber?
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Algebra.Com's Answer #241065 by stanbon(75887)\"\" \"About 
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After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber?
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\n" ); document.write( "Robber DATA:
\n" ); document.write( "rate = 12 mph ; time = x hrs ; distance = 12x miles
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\n" ); document.write( "Marshall DATA:
\n" ); document.write( "rate = 16 mph ; time = x-(1/6) hr distance = 16(x-(1/6)) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "12x = 16(x-(1/6))
\n" ); document.write( "12x = 16x-(16/6)
\n" ); document.write( "-4x = -(16/6)
\n" ); document.write( "x = 2/3 hr
\n" ); document.write( "----
\n" ); document.write( "x-(1/6) = (4/6)-(1/6) = 1/2 hr (time needed for Marshall to catch robber)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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