document.write( "Question 336175: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution?\r
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document.write( "I have made a table and tried to work many algebraic solutions but cannot come up with one. \n" );
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Algebra.Com's Answer #241060 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution? \n" ); document.write( "------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol+alcohol = alcohol \n" ); document.write( "0.30x + 0.80*80 = 0.50(x+80) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "30x + 80*80 = 50x + 50*80 \n" ); document.write( "-20x = -30*80 \n" ); document.write( "x = (3/2)80 \n" ); document.write( "x = 120 liters (amt of 30% solution needed in the mixture) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |