document.write( "Question 336175: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution?\r
\n" ); document.write( "\n" ); document.write( "I have made a table and tried to work many algebraic solutions but cannot come up with one.
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Algebra.Com's Answer #241060 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol+alcohol = alcohol
\n" ); document.write( "0.30x + 0.80*80 = 0.50(x+80)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "30x + 80*80 = 50x + 50*80
\n" ); document.write( "-20x = -30*80
\n" ); document.write( "x = (3/2)80
\n" ); document.write( "x = 120 liters (amt of 30% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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