document.write( "Question 336099: Hi - function question....\r
\n" ); document.write( "\n" ); document.write( "There is the function g(x) = K(x+3)(x-3) for some constant K. \r
\n" ); document.write( "\n" ); document.write( "If g(a-1.2) = 0 and a>0, what is the value of a?\r
\n" ); document.write( "\n" ); document.write( "thank you - we are at a loss....\r
\n" ); document.write( "\n" ); document.write( "Fiona
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Algebra.Com's Answer #241036 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Find the value of a if:
\n" ); document.write( "\"g%28x%29+=+K%28x%2B3%29%28x-3%29\" K = some constant. and if...
\n" ); document.write( "\"g%28a-1.2%29+=+0\" and \"a%3E0\"
\n" ); document.write( "In the given function \"g%28x%29+=+K%28x%2B3%29%28x-3%29\" simplify.
\n" ); document.write( "\"g%28x%29+=+K%28x%5E2-9%29\" For every x, replace with (a-1.2)
\n" ); document.write( "\"g%28a-1.2%29+=+K%28%28a-1.2%29%5E2-9%29%29\" Expand the right side.
\n" ); document.write( "\"g%28a-1.2%29+=+K%28%28a%5E2-2.4a%2B1.44%29-9%29\"
\n" ); document.write( "\"g%28a-1.2%29+=+K%28a%5E2-2.4a-7.56%29\" Now set this equal to zero since:\"g%28a-1.2%29=0\"
\n" ); document.write( "\"K%28a%5E2-2.4a-7.56%29+=+0\" Apply the zero product rule:
\n" ); document.write( "\"K+=+0\" or \"a%5E2-2.4a-7.96+=+0\"
\n" ); document.write( "\"a%5E2-2.4a-7.56+=+0\" You can use the quadratic formula to solve this and you should get:
\n" ); document.write( "\"a+=+4.2\" or \"a+=+-1.8\"
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