document.write( "Question 336070: A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is 2/3? Explain \n" ); document.write( "
Algebra.Com's Answer #241026 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is 2/3? \n" ); document.write( "--- \n" ); document.write( "Let the number of green skittles added be \"x\". \n" ); document.write( "Total # of skittles in the bag = 5+x + 3 +2 + 6 = 16+x \n" ); document.write( "----------------- \n" ); document.write( "P(selecting a green skittle) = (x+5)/(x+16) = 2/3 \n" ); document.write( "--- \n" ); document.write( "Solve for \"x: \n" ); document.write( "Cross-multiply to get: \n" ); document.write( "3(x+5) = 2(x+16) \n" ); document.write( "3x+15 = 2x + 32 \n" ); document.write( "x = 17 (# of green skittles added) \n" ); document.write( "======================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |