document.write( "Question 336070: A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is 2/3? Explain \n" ); document.write( "
Algebra.Com's Answer #241026 by stanbon(75887)\"\" \"About 
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A bag contains 5 green, 3 red, 2 orange and 6 yellow skittles. How many green skittes must have been added to the bag so that the probability of randomly picking a green skittle is 2/3?
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\n" ); document.write( "Let the number of green skittles added be \"x\".
\n" ); document.write( "Total # of skittles in the bag = 5+x + 3 +2 + 6 = 16+x
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\n" ); document.write( "P(selecting a green skittle) = (x+5)/(x+16) = 2/3
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\n" ); document.write( "Solve for \"x:
\n" ); document.write( "Cross-multiply to get:
\n" ); document.write( "3(x+5) = 2(x+16)
\n" ); document.write( "3x+15 = 2x + 32
\n" ); document.write( "x = 17 (# of green skittles added)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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