document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=336061>Question 336061</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving this problem.\r<BR>\n" );
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document.write( "A car travels 300 km in the same amount of time that a freight train travels 200 km. The speed of the car is 20km/hr more than the speed of the train. Find the speed of both the car and the train. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #241007 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=241007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of train be x km/hr<BR>\n" );
document.write( "speed of car = x+20 km/hr<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance by car = 300 km<BR>\n" );
document.write( "distance by train = 200 km<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Time taken by both is same<BR>\n" );
document.write( "200/x = 300 (x+20)<BR>\n" );
document.write( "300x = 200(x+20)<BR>\n" );
document.write( "300x = 200x +4000<BR>\n" );
document.write( "add -200x<BR>\n" );
document.write( "300x-200x=4000<BR>\n" );
document.write( "100x = 4000<BR>\n" );
document.write( "x = 40 km/hr speed of train<BR>\n" );
document.write( "x+20 = 40 +20 = 60km/hr. speed of car<BR>\n" );
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