document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=336003>Question 336003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I have got a question that is to do with calculus but i couldn't find a section covering it above so I put in alegaebra equations, sorry if that was a problem. \r<BR>\n" );
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document.write( "Ok the question I have that i need help with is \"Using an algebraic method, determine the equation of the catenary that you believe best models your necklace\". Baiscally I had to make earlier a parabola by tracing a chain and then find an equation to match that parabola which i had difficulty with. Now later on, on a much harder question it was required for the parabola to be shitfed upwards on the y-axis and the equation to be calculated.\r<BR>\n" );
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document.write( "I have obtained three coordinates that I tried to use but to no avail, they are\r<BR>\n" );
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document.write( "Turning Point (0, 10) and (30,27) and (54,79). If a negative x-vaule would make it easier then those three a coordinate that could also be used is- (-54, 79). Any help would be greatly appreciated. I was attempting to use the formula y=ax^2+bx+c, as this formula is what is needed to be solved, that a-value, b-value and c-value.<BR>\n" );
document.write( "Any help would be greatly appreciated.<BR>\n" );
document.write( "Thank you<BR>\n" );
document.write( "Keiran </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240983 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Using an algebraic method, determine the equation of the catenary that you believe best models your necklace\". Baiscally I had to make earlier a parabola by tracing a chain and then find an equation to match that parabola which i had difficulty with. Now later on, on a much harder question it was required for the parabola to be shitfed upwards on the y-axis and the equation to be calculated. <BR>\n" );
document.write( "I have obtained three coordinates that I tried to use but to no avail, they are <BR>\n" );
document.write( "Turning Point (0, 10) and (30,27) and (54,79). If a negative x-vaule would make it easier then those three a coordinate that could also be used is- (-54, 79). Any help would be greatly appreciated. I was attempting to use the formula y=ax^2+bx+c, as this formula is what is needed to be solved, that a-value, b-value and c-value.<BR>\n" );
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document.write( "Using:::::: ax^2 + bx + c = y<BR>\n" );
document.write( "(0,10):::::  0   +  0 + c = 10<BR>\n" );
document.write( "(30,27):::: a*30^2+b*30+c = 27<BR>\n" );
document.write( "(54,79):::: a*54^2+b*45+c = 79<BR>\n" );
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document.write( "Using Matrix:<BR>\n" );
document.write( "0::::0::::1::::10<BR>\n" );
document.write( "30^2:30:::1::::27<BR>\n" );
document.write( "54^2:54:::1::::79<BR>\n" );
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document.write( "a = 0.0296<BR>\n" );
document.write( "b = -0.3222<BR>\n" );
document.write( "c = 10<BR>\n" );
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document.write( "Note: By the way, a catenary is not a parabola.<BR>\n" );
document.write( "A catenary has its own equation form.  Check<BR>\n" );
document.write( "Google to see more about catenaries.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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