document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335894>Question 335894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following equation by the square root method? <BR>\n" );
document.write( "(3y+6)^2=36 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240982 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3y+6)^2=36<BR>\n" );
document.write( "Take the sqrt of both sides.<BR>\n" );
document.write( "3y+6=6<BR>\n" );
document.write( "3y=6-6<BR>\n" );
document.write( "3y=0<BR>\n" );
document.write( "y=0/6<BR>\n" );
document.write( "y=0 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "(3*0+6)^2=36<BR>\n" );
document.write( "6^2=36<BR>\n" );
document.write( "36=36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );