document.write( "Question 38579: Five men were to share treasure with long john silver. If the treasure were split into the following ratio 2:5:7:10:20:50. and the least amount any of the 6 pirates received was 14,000 pounds of gold. What is the total weight of the treasure??\r
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Algebra.Com's Answer #24093 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First I would add up the numbers given in the ratio:
\n" ); document.write( "2+5+7+10+20+50 = 94 shares. \r
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\n" ); document.write( "\n" ); document.write( "The one who receives the least amount, therefore, received 2 shares out of a total of 94 shares of the total treasure, or \"1%2F47\"th of the treasure. \r
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\n" ); document.write( "\n" ); document.write( "Let x = total treasure, then\r
\n" ); document.write( "\n" ); document.write( "\"+%281%2F47%29%2Ax+=+14000\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 47:
\n" ); document.write( "\"x+=+14000%2A47=658000\" pounds = total weight of gold. \r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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\n" ); document.write( "\n" ); document.write( "P.S. That's a LOT of gold!! Longjonsilver would have liked this one!! Maybe he will answer it also!!
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