document.write( "Question 38573: One garden hosecan fil an above-ground in 10 hours. A second hose can fill the pool twice as fast as the first one. If both hoses are used together to fill the pool, how many hours will it take?\r
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Algebra.Com's Answer #24092 by AnlytcPhil(1807)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "One garden hose can fill an above-ground in 10 hours. A second \r\n" );
document.write( "hose can fill the pool twice as fast as the first one. If both \r\n" );
document.write( "hoses are used together to fill the pool, how many hours will \r\n" );
document.write( "it take?\r\n" );
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document.write( "Let x = the number of hours it takes if both hoses are used\r\n" );
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document.write( ">>...One garden hose can fill an above-ground pool in 10 hours...<<\r\n" );
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document.write( "Therefore in 1 hour the first hose can fill 1/10th of the pool\r\n" );
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document.write( "Therefore, in x hours the first hose can fill x/10ths of the pool  \r\n" );
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document.write( ">>...A second hose can fill the pool twice as fast as the first one...<<\r\n" );
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document.write( "This tells us that the second hose can fill it in only 5 hours, since\r\n" );
document.write( "the first one can fill it in 10 hours.\r\n" );
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document.write( "Therefore in 1 hour the second hose can fill 1/5th of the pool\r\n" );
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document.write( "Therefore, in x hours the first can fill x/5ths of the pool \r\n" );
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document.write( "To get the equation:\r\n" );
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document.write( "(Fraction of pool the 1st hose fills in x hours) +\r\n" );
document.write( "             (Fraction of pool the 1st hose fills in x hours) =\r\n" );
document.write( "                            One pool filled in x hours\r\n" );
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document.write( "   x/10 + x/5 = 1\r\n" );
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document.write( "Can you solve that? If not post again\r\n" );
document.write( "Hint: clear of fractions by multiplying thru by LCD = 10\r\n" );
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document.write( "Answer: 3 1/3 hours or 3 hours 20 minutes.\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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