document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38578>Question 38578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Terry has 7 more quarters than dimes and has a total of $6.80. The number of quarters and dimes is 38. How many quarters and dimes does terry have?\r<BR>\n" );
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document.write( "Thanks for answering!:-) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24091 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let q = # of quarters.  Thus their value is 25q.<BR>\n" );
document.write( "Let d = # of dimes.  Thus their value is 10d.<BR>\n" );
document.write( "From the facts in the problem, we have<BR>\n" );
document.write( "q + d = 38<BR>\n" );
document.write( "25q + 10d = 680 ($6.80 expressed in cents)<BR>\n" );
document.write( "We also have a third equation, not common in these problems (q = d + 7) which incidentally is impossible...<BR>\n" );
document.write( "Let us solve the first for d and substitute into the second equation...<BR>\n" );
document.write( "d = 38 - q<BR>\n" );
document.write( "25q + 10(38 - q) = 680<BR>\n" );
document.write( "25q + 380 - 10q = 680<BR>\n" );
document.write( "15q = 300<BR>\n" );
document.write( "q = 20 and then <BR>\n" );
document.write( "d = 18 </SPAN>\n" );
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