document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335916>Question 335916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the solutions to 6x^2 + 5x - 4= 0. Is the sum of your solutions equal to\r<BR>\n" );
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document.write( " -b/a? Explain why the sum of the solutions to any quadratic equation is -b/a?.\r<BR>\n" );
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document.write( "(Hint: Use the quadratic formula.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240899 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the solutions to 6x^2 + 5x - 4= 0. Is the sum of your solutions equal to <BR>\n" );
document.write( "-b/a? <BR>\n" );
document.write( "Explain why the sum of the solutions to any quadratic equation is -b/a?. <BR>\n" );
document.write( "(Hint: Use the quadratic formula.)<BR>\n" );
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document.write( "1st solution: x1 = (-b/2a)+(sqrt(b^2-4ac)/(2a)<BR>\n" );
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document.write( "2nd solution: x2 = (-b/2a)-(sqrt(b^2-4ac)/(2a)<BR>\n" );
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document.write( "Adding you get: x1+x2 = 2(-b/2a) = -b/a<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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